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Proof step 15 from proof rightshift-8-01-01 (previous step)

0 ≤ i, # int2bytes(i) ≤ i→n(j) ⊦ j = 0, i >> 8 * j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 16:
⊦ 0 ≤ i → i >> j = i / 2 ^ abs(j)
Proof step 17:
0 ≤ i, 0 ≤ i, # int2bytes(i) ≤ i→n(j) ⊦ j = 0, i / 2 ^ abs(8 * j) = 0

Rule argument

seq: ⊦ 0 ≤ i → i >> j = i / 2 ^ abs(j) subst: [j, i] → [8 * j, i] rotate: F spec: intops inst: name: shiftright-pos-div-01

Additional information

Used terms: 8 * j, i