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Proof step 17 from proof rightshift-8-01-01 (previous step)

0 ≤ i, 0 ≤ i, # int2bytes(i) ≤ i→n(j) ⊦ j = 0, i / 2 ^ abs(8 * j) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
0 ≤ i, # int2bytes(i) ≤ i→n(j) ⊦ j = 0, i / 2 ^ (8 * abs(j)) = 0

Rule argument

Additional information

Used simplifier rules: ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ abs(i * j) = abs(i) * abs(j);