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Proof step 35 from proof rightshift-8-01-01 (previous step)

i < 0, # int2bytes(i) ≤ i→n(j) ⊦ j = 0, i >> 8 * j = ~1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 36:
⊦ ~(2 ^ (abs(j) - 1)) ≤ i ∧ i < 0 → i >> j = ~1
Proof step 37:
¬(~(2 ^ (abs(8 * j) - 1)) ≤ i ∧ i < 0), i < 0, # int2bytes(i) ≤ i→n(j) ⊦ j = 0, i >> 8 * j = ~1

Rule argument

seq: ⊦ ~(2 ^ (abs(j) - 1)) ≤ i ∧ i < 0 → i >> j = ~1 subst: [j, i] → [8 * j, i] rotate: F spec: intops inst: name: shiftright-neg-mone

Additional information

Used terms: 8 * j, i