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Proof step 37 from proof rightshift-8-01-01 (previous step)

¬(~(2 ^ (abs(8 * j) - 1)) ≤ i ∧ i < 0), i < 0, # int2bytes(i) ≤ i→n(j) ⊦ j = 0, i >> 8 * j = ~1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 38:
i < 0, # int2bytes(i) ≤ i→n(j), 2 ^ (8 * abs(j) - 1) + i < 0 ⊦ j = 0, i >> 8 * j = ~1

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ ~ i ≤ j ↔ 0 ≤ i + j;% ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ abs(i * j) = abs(i) * abs(j);