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Proof step 44 from proof rightshift-8-02 (previous step)

int2bytes(i) = by ', i < 0, i < ~128 ⊦ i >> 8 = ~1, ¬ ~256 ≤ i ∧ i % 256 ≠ 0, ¬ ~256 ≤ i ∧ i % 256 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 45:
⊦ i % 2 ^ abs(j) = 0 ∧ i < ~(2 ^ (abs(j) - 1)) ∧ j ≠ 0 → i >> j = i / 2 ^ abs(j)
Proof step 46:
¬(i % 2 ^ abs(8) = 0 ∧ i < ~(2 ^ (abs(8) - 1)) ∧ 8 ≠ 0), int2bytes(i) = by ', i < 0, i < ~128 ⊦ i >> 8 = ~1, ¬ ~256 ≤ i ∧ i % 256 ≠ 0, ¬ ~256 ≤ i ∧ i % 256 = 0
Proof step 52:
i % 2 ^ abs(8) = 0 ∧ i < ~(2 ^ (abs(8) - 1)) ∧ 8 ≠ 0, int2bytes(i) = by ', i < 0, i < ~128 ⊦ i / 2 ^ abs(8) = ~1, ¬ ~256 ≤ i ∧ i % 256 ≠ 0, ¬ ~256 ≤ i ∧ i % 256 = 0

Rule argument

seq: ⊦ i % 2 ^ abs(j) = 0 ∧ i < ~(2 ^ (abs(j) - 1)) ∧ j ≠ 0 → i >> j = i / 2 ^ abs(j) subst: [j, i] → [8, i] rotate: F spec: intops inst: name: shiftright-neg-div-01

Additional information

Used terms: 8, i