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Proof step 52 from proof rightshift-8-02 (previous step)

i % 2 ^ abs(8) = 0 ∧ i < ~(2 ^ (abs(8) - 1)) ∧ 8 ≠ 0, int2bytes(i) = by ', i < 0, i < ~128 ⊦ i / 2 ^ abs(8) = ~1, ¬ ~256 ≤ i ∧ i % 256 ≠ 0, ¬ ~256 ≤ i ∧ i % 256 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 53:
int2bytes(i) = by ', i % 256 = 0, i < 0, i < ~128, ~256 ≤ i ⊦ i / 256 = ~1

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward)%j0 ≠ 0, j ≤ j0 ⊦ i < (* j) → i < (* j0);