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Proof step 3 from proof setShort-theorem-01 (previous step)

# fillsgn(2, int2bytes(s2i(sho))) = 2 ⊦ fillsgn(2, int2bytes(s2i(sho))) = i2b(s2i(sho) i>> 8) ' + i2b(s2i(sho)) '

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ bytes ≠ [] → # bytes = # bytes.rest + 1
Proof step 5:
fillsgn(2, int2bytes(s2i(sho))) ≠ [], # fillsgn(2, int2bytes(s2i(sho))).rest + 1 = 2 ⊦ fillsgn(2, int2bytes(s2i(sho))) = i2b(s2i(sho) i>> 8) ' + i2b(s2i(sho)) '

Rule argument

spec: list-data inst: bytelist name: length-rest-intro seq: ⊦ bytes ≠ [] → # bytes = # bytes.rest + 1 subst: [bytes] → [fillsgn(2, int2bytes(s2i(sho)))] flags: rewrite

Additional information

Used simplifier rules: fillsgn-not-empty: ⊦ fillsgn(n, int2bytes(i)) ≠ []; Used terms: fillsgn(2, int2bytes(s2i(sho)))