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Proof step 5 from proof setShort-theorem-01 (previous step)

fillsgn(2, int2bytes(s2i(sho))) ≠ [], # fillsgn(2, int2bytes(s2i(sho))).rest + 1 = 2 ⊦ fillsgn(2, int2bytes(s2i(sho))) = i2b(s2i(sho) i>> 8) ' + i2b(s2i(sho)) '

User applied rule insert elim lemma

And obtained the following new goals

Rule argument

spec: list-data inst: bytelist name: elim-1 seq: ⊦ bytes ≠ [] → (by = bytes.first ∧ bytes0 = bytes.rest ↔ bytes = by + bytes0) subst: [bytes, by, bytes0] → [fillsgn(2, int2bytes(s2i(sho))), by, bytes] flags: []

Additional information

Used simplifier rules: ⊦ bytes ≠ [] → (by = bytes.first ∧ bytes0 = bytes.rest ↔ bytes = by + bytes0); (elim) Used terms: fillsgn(2, int2bytes(s2i(sho))), by, bytes