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Proof step 12 from proof setShort-theorem (previous step)

fillsgn(2, int2bytes(s2i(sho))) = by ' + by0 ' ⊦ # int2bytes(s2i(sho)) ≠ 1, by0 = i2b(s2i(sho)) ∧ by = i2b(s2i(sho) >> 8), s2i(sho) ≠ b2i(i2b(s2i(sho))) ∧ ¬ 2 < # int2bytes(s2i(sho))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: int2bytes-len-one-01: ⊦ # int2bytes(i) = 1 ↔ int2bytes(i) = i2b(i) ';%int2bytes-len-one: ⊦ int2bytes(i) = by ' ↔ i = b2i(by);