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Proof step 8 from proof setShort-theorem (previous step)

fillsgn(2, int2bytes(s2i(sho))) = by ' + by0 ' ⊦ by0 = i2b(s2i(sho)) ∧ by = i2b(s2i(sho) >> 8), s2i(sho) ≠ b2i(i2b(s2i(sho))) ∧ ¬ 2 < # int2bytes(s2i(sho))

User applied rule cut formula

And obtained the following new goals

Proof step 9:
# int2bytes(s2i(sho)) ≠ 1, fillsgn(2, int2bytes(s2i(sho))) = by ' + by0 ' ⊦ by0 = i2b(s2i(sho)) ∧ by = i2b(s2i(sho) >> 8), s2i(sho) ≠ b2i(i2b(s2i(sho))) ∧ ¬ 2 < # int2bytes(s2i(sho))
Proof step 12:
fillsgn(2, int2bytes(s2i(sho))) = by ' + by0 ' ⊦ # int2bytes(s2i(sho)) ≠ 1, by0 = i2b(s2i(sho)) ∧ by = i2b(s2i(sho) >> 8), s2i(sho) ≠ b2i(i2b(s2i(sho))) ∧ ¬ 2 < # int2bytes(s2i(sho))

Rule argument

fma: # int2bytes(s2i(sho)) ≠ 1

Additional information

Used formulas: # int2bytes(s2i(sho)) ≠ 1