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Proof step 15 from proof setShort-theorem (previous step)

fillsgn(2, i2b(s2i(sho)) ') = by ' + by0 ' ⊦ by0 = i2b(s2i(sho)) ∧ by = i2b(b2i(i2b(s2i(sho))) >> 8)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

name: fillsgn-neg rotate: F subst: [bytes, n] → [i2b(s2i(sho)) ', 2]

Additional information

Used simplifier rules: bytes2int-one: ⊦ bytes2int(by ') = b2i(by);% ⊦ # by ' = 0 +1;% ⊦ mklist(by, 1) = by ';% ⊦ bytes + by ' = bytes0 + by0 ' ↔ bytes = bytes0 ∧ by = by0;% ⊦ by ' = by0 ' ↔ by = by0;% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ b2i(by) < 0 → b2i(by) >> 8 = ~1; Used terms: i2b(s2i(sho)) ', 2