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Proof step 17 from proof setShort-theorem (previous step)

¬(# i2b(s2i(sho)) ' < 2 ∧ bytes2int(i2b(s2i(sho)) ') < 0), fillsgn(2, i2b(s2i(sho)) ') = by ' + by0 ' ⊦ by0 = i2b(s2i(sho)) ∧ by = i2b(b2i(i2b(s2i(sho))) >> 8)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: bytes2int-one: ⊦ bytes2int(by ') = b2i(by);% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ 0 ≤ b2i(by) → b2i(by) >> 8 = 0;% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ # by ' = 0 +1;