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Proof step 18 from proof short-2bytes (previous step)

0 < band(b2i(by0), 255) + 256 * b2i(by), 32767 < band(b2i(by0), 255) + 256 * b2i(by) ⊦

User applied rule cut formula

And obtained the following new goals

Rule argument

fma: 32767 < band(b2i(by0), 255) + 256 * 127

Additional information

Used simplifier rules: ⊦ (* j) < i0 + (* j0) ↔ j - j0 < i0;% ⊦ 0 ≤ i ∧ i ≤ i0 → ¬ i0 < band(i, j);% ⊦ band(i, band(i0, j)) = band(band(i, i0), j);% ⊦ band(i, j) = band(j, i);% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i; Used formulas: 32767 < band(b2i(by0), 255) + 256 * 127