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Proof step 19 from proof short-2bytes (previous step)

0 < band(b2i(by0), 255) + 256 * b2i(by), 32767 < band(b2i(by0), 255) + 256 * b2i(by) ⊦ 32767 < band(b2i(by0), 255) + 256 * 127

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 20:
⊦ ¬ i < j ↔ ¬ ¬(i = j ∨ j < i)
Proof step 21:
0 < band(b2i(by0), 255) + 256 * b2i(by), 32767 < band(b2i(by0), 255) + 256 * b2i(by) ⊦ ¬(32767 = band(b2i(by0), 255) + 256 * 127 ∨ band(b2i(by0), 255) + 256 * 127 < 32767)

Rule argument

seq: ⊦ ¬ i < j ↔ ¬ ¬(i = j ∨ j < i) subst: [j, i] → [band(b2i(by0), 255) + 256 * 127, 32767] rotate: F spec: int-basic1 inst: name: l

Additional information

Used simplifier rules: ⊦ band(i, j) = band(j, i); Used terms: band(b2i(by0), 255) + 256 * 127, 32767