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Proof step 21 from proof short-2bytes (previous step)

0 < band(b2i(by0), 255) + 256 * b2i(by), 32767 < band(b2i(by0), 255) + 256 * b2i(by) ⊦ ¬(32767 = band(b2i(by0), 255) + 256 * 127 ∨ band(b2i(by0), 255) + 256 * 127 < 32767)

User applied rule prop simplification

And obtained the following new goals

Rule argument

pos: right 1

Additional information