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Proof step 10 from proof test-divides-01 (previous step)

mkDecimal(3 * i, abs(i0)) = mkDecimal(1, 0) ⊦

User applied rule induction

And obtained the following new goals

Proof step 11:
mkDecimal(3 * i, abs(i0)) = mkDecimal(1, 0), ∀ i1, i0. i→n(i1) < i→n(i) → mkDecimal(3 * i1, abs(i0)) = mkDecimal(1, 0) → false ⊦ false

Rule argument

indvar: i→n(i) wfpred: <

Additional information

Used simplifier rules: <; (wellfounded) Used terms: i→n(i)