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Proof step 9 from proof test-divides-01 (previous step)

mkDecimal(3 * i, abs(0) + abs(i0)) = mkDecimal(1, 0) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
mkDecimal(3 * i, abs(i0)) = mkDecimal(1, 0) ⊦

Rule argument

Additional information

Used simplifier rules: add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-zero: ⊦ i + 0 = i; from specification int-basic2