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Proof step 19 from proof abs-any-def (previous step)

∀ i0, j. i→n(i0) < i→n(0) → true → abs(mkDecimal(i0, j)) = mkDecimal(abs(i0), j) ⊦ j = 0, abs(mkDecimal(0, abs(j) - 1)) = mkDecimal(0, j)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 20:
⊦ mkDecimal(0, j) = mkDecimal(0, 0)
Proof step 21:
∀ i0, j. i→n(i0) < i→n(0) → true → abs(mkDecimal(i0, j)) = mkDecimal(abs(i0), j) ⊦ j = 0, abs(mkDecimal(0, 0)) = mkDecimal(0, j)

Rule argument

spec: decimal inst: name: mkDecimal-zero seq: ⊦ mkDecimal(0, j) = mkDecimal(0, 0) subst: [j] → [abs(j) - 1] flags: rewrite

Additional information

Used terms: abs(j) - 1