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Proof step 21 from proof abs-any-def (previous step)

∀ i0, j. i→n(i0) < i→n(0) → true → abs(mkDecimal(i0, j)) = mkDecimal(abs(i0), j) ⊦ j = 0, abs(mkDecimal(0, 0)) = mkDecimal(0, j)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: inst: name: abs-def seq: ⊦ abs(dec_i) = mkDecimal(abs(dec_i.int), dec_i.scale) subst: [dec_i] → [mkDecimal(0, 0)] flags: rewrite, current

Additional information

Used simplifier rules: intvalue-zero: ⊦ mkDecimal(0, j).int = 0; from specification decimal%scale-zero: ⊦ mkDecimal(0, j).scale = 0; from specification decimal%eq-zero: ⊦ mkDecimal(i, j) = mkDecimal(0, j0) ↔ i = 0; from specification decimal Used terms: mkDecimal(0, 0)