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Proof step 3 from proof maxScale-pot10 (previous step)

0 ≤ i, ∀ i0. i→n(i0) < i→n(i) → 0 ≤ i0 → maxScale(10 ^ i0) = i0 ⊦ maxScale(10 ^ i) = i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ 0 < i → j ^ i = j ^ i -1 * j
Proof step 5:
¬ 0 < i, 0 ≤ i, ∀ i0. i→n(i0) < i→n(i) → 0 ≤ i0 → maxScale(10 ^ i0) = i0 ⊦ maxScale(10 ^ i) = i
Proof step 8:
0 < i, 0 ≤ i, ∀ i0. i→n(i0) < i→n(i) → 0 ≤ i0 → maxScale(10 ^ i0) = i0 ⊦ maxScale(10 ^ i -1 * 10) = i

Rule argument

spec: int-pot inst: name: Pot-pos seq: ⊦ 0 < i → j ^ i = j ^ i -1 * j subst: [i, j] → [i, 10] flags: rewrite

Additional information

Used terms: i, 10