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Proof step 5 from proof maxScale-pot10 (previous step)

¬ 0 < i, 0 ≤ i, ∀ i0. i→n(i0) < i→n(i) → 0 ≤ i0 → maxScale(10 ^ i0) = i0 ⊦ maxScale(10 ^ i) = i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
∀ i0. i→n(i0) < i→n(0) → 0 ≤ i0 → maxScale(10 ^ i0) = i0 ⊦ maxScale(1) = 0

Rule argument

Additional information

Used simplifier rules: anti: ⊦ i ≤ j → (j ≤ i ↔ i = j); from specification int-abs%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs