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Proof step 1 from proof hexbyte-byte (conclusion)
# str = 2 ⊦ hexbyte((* str)) = i2b(hexchar(str.char1) * 16 + hexchar(str.rstring.char1))
Special step normalize
And obtained the following new goals
Proof step 2
:
# str = 2 ⊦ hexbyte(str) = i2b(hexchar(str.char1) * 16 + hexchar(str.rstring.char1))