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Proof step 2 from proof hexbyte-byte (previous step)

# str = 2 ⊦ hexbyte(str) = i2b(hexchar(str.char1) * 16 + hexchar(str.rstring.char1))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ hexbyte(str) = i2b(hex(str))
Proof step 4:
# str = 2 ⊦ i2b(hex(str)) = i2b(hexchar(str.char1) * 16 + hexchar(str.rstring.char1))

Rule argument

spec: hexstring inst: name: hexbyte seq: ⊦ hexbyte(str) = i2b(hex(str)) subst: [str] → [str] flags: rewrite, current

Additional information

Used terms: str