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Proof step 5 from proof hexbyte-byte (previous step)

# str = 2 ⊦ i2b(hex(str)) = i2b(hexchar(str.char1) * 16 + hexchar(str.rstring.char1))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
str ≠ "" ⊦ hex((* str)) = hexchar(str.char1) * 16 ^ (n→i(# str) - 1) + hex(str.rstring)
Proof step 7:
str ≠ "", # str = 2 ⊦ i2b(hexchar(str.char1) * 16 ^ (n→i(# str) - 1) + hex(str.rstring)) = i2b(hexchar(str.char1) * 16 + hexchar(str.rstring.char1))

Rule argument

spec: hexstring inst: name: numhex-rec seq: str ≠ "" ⊦ hex((* str)) = hexchar(str.char1) * 16 ^ (n→i(# str) - 1) + hex(str.rstring) subst: [str] → [str] flags: rewrite, current

Additional information

Used simplifier rules: ⊦ # "" = 0; Used terms: str