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Proof step 7 from proof hexbyte-byte (previous step)

str ≠ "", # str = 2 ⊦ i2b(hexchar(str.char1) * 16 ^ (n→i(# str) - 1) + hex(str.rstring)) = i2b(hexchar(str.char1) * 16 + hexchar(str.rstring.char1))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information