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Proof step 16 from proof max_exp-div-not (previous step)

max_exp(2, 11) = 3, 2 | 4 ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: inst: name: max_exp-zero-01 seq: ⊦ ¬ i | j ∧ prime(i) ∧ 0 < j → max_exp(i, j) = 0 subst: [j, i] → [11, 2] flags: rewrite, current

Additional information

Used terms: 11, 2