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Proof step 15 from proof max_exp-div-not (previous step)

prime(2) ∧ 2 | 4 ∧ 0 < 4, max_exp(2, 11) = max_exp(2, 2) + max_exp(2, 4 / 2) + 1 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: max_exp-same: ⊦ prime(i) → max_exp(i, i) = 1;%prime-two-01: ⊦ prime(2); from specification int-gcd%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2