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Proof step 9 from proof max_exp-div-not (previous step)

max_exp(2, 11) = max_exp(2, 2) + max_exp(2, 4) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ prime(i) ∧ i | j ∧ 0 < j → max_exp(i, j) = max_exp(i, j / i) + 1
Proof step 11:
¬(prime(2) ∧ 2 | 4 ∧ 0 < 4), max_exp(2, 11) = max_exp(2, 2) + max_exp(2, 4) ⊦
Proof step 15:
prime(2) ∧ 2 | 4 ∧ 0 < 4, max_exp(2, 11) = max_exp(2, 2) + max_exp(2, 4 / 2) + 1 ⊦

Rule argument

spec: inst: name: max_exp-rec seq: ⊦ prime(i) ∧ i | j ∧ 0 < j → max_exp(i, j) = max_exp(i, j / i) + 1 subst: [j, i] → [4, 2] flags: rewrite, current

Additional information

Used terms: 4, 2