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Proof step 1 from proof max_exp-divides (conclusion)

⊦ 0 < j ∧ prime(i) → i ^ max_exp(i, j) | j ∧ ¬ i | j / i ^ max_exp(i, j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
prime(i), 0 < j ⊦ i ^ max_exp(i, j) | j ∧ ¬ i | j / i ^ max_exp(i, j)

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs