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Proof step 2 from proof max_exp-divides (previous step)

prime(i), 0 < j ⊦ i ^ max_exp(i, j) | j ∧ ¬ i | j / i ^ max_exp(i, j)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ max_exp(i, j) = n→i(#oc(i, all_prime_divisors(j)))
Proof step 4:
prime(i), 0 < j ⊦ i ^ n→i(#oc(i, all_prime_divisors(j))) | j ∧ ¬ i | j / i ^ n→i(#oc(i, all_prime_divisors(j)))

Rule argument

spec: inst: name: max_exp-def seq: ⊦ max_exp(i, j) = n→i(#oc(i, all_prime_divisors(j))) subst: [j, i] → [j, i] flags: rewrite, current

Additional information

Used terms: j, i