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Proof step 2 from proof max_exp-pos-03 (previous step)

max_exp(i0, j0) + max_exp(i, j) ≤ 0 ⊦ max_exp(i0, j0) = 0 ∧ max_exp(i, j) = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: int-abs inst: name: lels-02 seq: ⊦ i ≠ j → (i ≤ j ↔ i < j) subst: [j, i] → [0, max_exp(i0, j0) + max_exp(i, j)] flags: rewrite

Additional information

Used simplifier rules: max_exp-pos-01: ⊦ ¬ max_exp(i0, j0) + max_exp(i, j) < 0;%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2 Used terms: 0, max_exp(i0, j0) + max_exp(i, j)