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Proof step 4 from proof max_exp-pos-03 (previous step)

¬ max_exp(i0, j0) + max_exp(i, j) ≠ 0, max_exp(i0, j0) + max_exp(i, j) ≤ 0 ⊦ max_exp(i0, j0) = 0 ∧ max_exp(i, j) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
max_exp(i0, j0) + max_exp(i, j) = 0 ⊦ max_exp(i0, j0) = 0 ∧ max_exp(i, j) = 0

Rule argument

Additional information

Used simplifier rules: forward-le-04: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward) from specification int-abs