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Proof step 4 from proof max_exp-rec (previous step)

prime(i), i | j, 0 < j ⊦ n→i(#oc(i, all_prime_divisors(j))) = max_exp(i, j / i) + 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ max_exp(i, j) = n→i(#oc(i, all_prime_divisors(j)))
Proof step 6:
prime(i), i | j, 0 < j ⊦ n→i(#oc(i, all_prime_divisors(j))) = n→i(#oc(i, all_prime_divisors(j / i))) + 1

Rule argument

spec: inst: name: max_exp-def seq: ⊦ max_exp(i, j) = n→i(#oc(i, all_prime_divisors(j))) subst: [j, i] → [j / i, i] flags: rewrite, current

Additional information

Used terms: j / i, i