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Proof step 6 from proof max_exp-rec (previous step)

prime(i), i | j, 0 < j ⊦ n→i(#oc(i, all_prime_divisors(j))) = n→i(#oc(i, all_prime_divisors(j / i))) + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
prime(i), i | j, 0 < j ⊦ #oc(i, all_prime_divisors(j)) = #oc(i, all_prime_divisors(j / i)) + 1

Rule argument

Additional information

Used simplifier rules: add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%nat2int-05: ⊦ n→i(m) = n→i(n) + 1 ↔ m = n + 1; from specification intnat