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Proof step 10 from proof prime-divides-pot (previous step)

i * j = i0 ^ i1 * i0, prime(i), 0 ≤ i1 ⊦ gcd(i, i0 ^ i1) = 1, i | i0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: int-gcd inst: name: gcd-one-prime seq: ⊦ prime(i) ∧ ¬ i | j → gcd(i, j) = 1 subst: [j, i] → [i0 ^ i1, i] flags: rewrite

Additional information

Used terms: i0 ^ i1, i