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Proof step 9 from proof prime-divides-pot (
previous step
)
¬(gcd(i, i0 ^ i1) = 1 ∧ i * j = i0 ^ i1 * i0), i * j = i0 ^ i1 * i0, prime(i), 0 ≤ i1 ⊦ i | i0
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 10
:
i * j = i0 ^ i1 * i0, prime(i), 0 ≤ i1 ⊦ gcd(i, i0 ^ i1) = 1, i | i0
Rule argument
Additional information