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Proof step 10 from proof cong-crt (previous step)

prime(j), prime(j0), 0 < i, j | abs(i - 1), j0 | i - 1 ⊦ j = j0, j * j0 | i - 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
j0 | i - 1, prime(j), prime(j0), 0 < i, j | i - 1 ⊦ j = j0, j * j0 | i - 1

Rule argument

Additional information

Used simplifier rules: abs-16: ⊦ 0 < j → abs(j) = j; from specification int-abs%abs-09: ⊦ 0 < i → abs(i - 1) = abs(i) - 1; from specification int-abs