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Proof step 11 from proof cong-crt (previous step)

j0 | i - 1, prime(j), prime(j0), 0 < i, j | i - 1 ⊦ j = j0, j * j0 | i - 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 12:
⊦ i | j ↔ (∃ i0. i * i0 = j)
Proof step 13:
∃ i0. j0 * i0 = i - 1, prime(j), prime(j0), 0 < i, j | i - 1 ⊦ j = j0, j * j0 | i - 1

Rule argument

spec: int-gcd inst: name: divides seq: ⊦ i | j ↔ (∃ i0. i * i0 = j) subst: [j, i] → [i - 1, j0] flags: rewrite

Additional information

Used terms: i - 1, j0