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Proof step 2 from proof congmod-def-mod (previous step)

0 < j ⊦ ≡mod(i, i0, j) ↔ i |%| j = i0 |%| j

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: int-mod inst: name: congmod-def seq: ⊦ ≡mod(i, i0, j) ↔ j | abs(i - i0) subst: [j, i0, i] → [j, i0, i] flags: rewrite, current

Additional information

Used terms: j, i0, i