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Proof step 4 from proof congmod-def-mod (previous step)

0 < j ⊦ j | abs(i - i0) ↔ i |%| j = i0 |%| j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
0 < j ⊦ j | i - i0 ↔ i |%| j = i0 |%| j

Rule argument

Additional information

Used simplifier rules: div-abs-02: ⊦ i | abs(j) ↔ i | j; from specification int-gcd