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Proof step 16 from proof congmod-inverse (previous step)

gcd(abs(i), abs(j)) = 1 ⊦ ¬ abs(j) ≤ 1, ∃ i0. ≡mod(i * i0, 1, j), 1 < abs(j) ∧ 1 < abs(i)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
gcd(abs(i), abs(j)) = 1, abs(j) ≤ 1 ⊦ ∃ i0. ≡mod(i * i0, 1, j)

Rule argument

Additional information

Used simplifier rules: lenls: ⊦ i ≤ j → ¬ j < i; from specification int-abs