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Theorem congmod-inverse
⊦ gcd(i, j) = 1 → (∃ i0. ≡mod(i * i0, 1, j))
Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment: i0 is the the multiplicative modulo inverse: z = x ^-1 mod n ⇔ z * x ≡ 1 mod n, i.e. ≡mod(z * x, 1, n).
Used by:
congmod-inverse-pos
,
fermat-2
,
Used by units in proved state:
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 19
Proof steps: 36
Used lemmas:
congmod-def
,
cong-one-01
,
cong-one
,
cong-zero
,
cong-same
,
Used spec theorems:
int-gcd
/
gcd-mod-one-01
int-gcd
/
gcd-abs-rew-02
int-abs
/
sub-same-01
Used simplifier rules:
int-abs
/
lels
int-mult
/
Mult-zero
int-mult
/
one
int-gcd
/
gcd-com
int-abs
/
lenls
int-abs
/
abs-01
int-mult
/
eq-one
int-abs
/
abs-one-01
int-gcd
/
gcd-one-01
int-abs
/
absle
int-mult
/
one-01
int-div
/
div-elim-pospos
int-abs
/
forward-le-01
int-mult
/
zero-ge
int-gcd
/
div-abs
int-abs
/
forward-le-02
oelem
/intlista/
transitivity
int-abs
/
lels-01
int-gcd
/
gcd-zero-04
int-abs
/
abs-08
int-gcd
/
div-zero-zero
int-mult
/
minus-one-01
int-abs
/
neg-02
int-basic2
/
zero-04
int-abs
/
mone-06
int-abs
/
zero-gels-04
int-abs
/
numadd-01
int-abs
/
negeq
int-div
/
mod-neg-01
int-abs
/
abs-07
int-mult
/
minus-left
int-gcd
/
div-abs-02
int-abs
/
abs-neg
int-abs
/
subsub
int-div
/
div-elim-negpos
int-abs
/
numlelsdel-01
int-abs
/
forward-le-04
int-abs
/
forward-lels
int-basic1
/
forward-pos
int-abs
/
forward-le-05
oelem
/intlista/
lel
int-mult
/
commutativity
int-mult
/
associativity
int-abs
/
zero-gels-01
int-mult
/
zero-ls
int-abs
/
abs-06
int-abs
/
sub-eq
int-basic2
/
add-c
int-basic2
/
add-a
int-abs
/
minus-add