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Proof step 2 from proof mod-rec-any (previous step)

0 < j ⊦ i |%| j = (i - j) |%| j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ j ≤ i ∧ 0 < j → i |%| j = (i - j) |%| j
Proof step 4:
¬(j ≤ i ∧ 0 < j), 0 < j ⊦ i |%| j = (i - j) |%| j

Rule argument

spec: int-mod inst: name: mod-rec seq: ⊦ j ≤ i ∧ 0 < j → i |%| j = (i - j) |%| j subst: [j, i] → [j, i] flags: rewrite, current

Additional information

Used terms: j, i