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Proof step 4 from proof mod-rec-any (previous step)

¬(j ≤ i ∧ 0 < j), 0 < j ⊦ i |%| j = (i - j) |%| j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
0 < j, i < j ⊦ i |%| j = (i - j) |%| j

Rule argument

Additional information

Used simplifier rules: lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs