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Proof step 5 from proof mod-rec-any (previous step)

0 < j, i < j ⊦ i |%| j = (i - j) |%| j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ 0 ≤ i ∧ i < j → i |%| j = i
Proof step 7:
¬(0 ≤ i ∧ i < j), 0 < j, i < j ⊦ i |%| j = (i - j) |%| j
Proof step 10:
0 ≤ i ∧ i < j, 0 < j, i < j ⊦ i = (i - j) |%| j

Rule argument

spec: int-mod inst: name: mod-zero seq: ⊦ 0 ≤ i ∧ i < j → i |%| j = i subst: [j, i] → [j, i] flags: rewrite, current

Additional information

Used terms: j, i