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Proof step 19 from proof bits2int-range (previous step)

¬ bits.first ∧ bits ≠ [], # bits = m + 1 ⊦ bits = [], ¬ 2 ^ n→i(m) + bits2uint(bits) < 0 ∧ ¬ 2 ^ n→i(m) ≤ bits2uint(bits)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
# bits = m + 1 ⊦ bits = [], bits.first, ¬ 2 ^ n→i(m) + bits2uint(bits) < 0 ∧ ¬ 2 ^ n→i(m) ≤ bits2uint(bits)

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;% ⊦ ¬ i < j ↔ j ≤ i;