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Proof step 20 from proof bits2int-range (previous step)

# bits = m + 1 ⊦ bits = [], bits.first, ¬ 2 ^ n→i(m) + bits2uint(bits) < 0 ∧ ¬ 2 ^ n→i(m) ≤ bits2uint(bits)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 21:
bits = boolvar + bits0, # bits = m + 1 ⊦ bits = [], boolvar, ¬ 2 ^ n→i(m) + bits2uint(bits) < 0 ∧ ¬ 2 ^ n→i(m) ≤ bits2uint(bits)

Rule argument

seq: bits ≠ [] ⊦ (boolvar ↔ bits.first) ∧ bits0 = bits.rest ↔ bits = boolvar + bits0 subst: [bits, boolvar, bits0] → [bits, boolvar, bits0] rotate: T spec: list-data inst: bitlista name: elim-list-c

Additional information

Used simplifier rules: bits ≠ [] ⊦ (boolvar ↔ bits.first) ∧ bits0 = bits.rest ↔ bits = boolvar + bits0; (elim) Used terms: bits, boolvar, bits0