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Proof step 10 from proof bits2int-rec-03 (previous step)

true ∈ bits0, false ∈ bits0 ⊦ bits2uint(bitsinvert(bits0)) + 1 = bits2uint(bitsinvert(bits0) +1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ bits ≠ [] → bits2uint(bits +1) = bits2uint(bits) + 1

Rule argument

name: bits2uint-succ rotate: F subst: [bits] → [bitsinvert(bits0)]

Additional information

Used simplifier rules: bits2uint-base: ⊦ bits2uint([]) = 0;%bits2uint-one-03: ⊦ bits2uint(true ') = 1;% ⊦ i + j = j + i;% ⊦ bitsinvert(bits) = [] ↔ bits = [];% ⊦ bitsinvert([]) = [];% ⊦ [] +1 = true '; Used terms: bitsinvert(bits0)