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Proof step 9 from proof bits2int-rec-03 (previous step)

true ∈ bits0, false ∈ bits0 ⊦ bits2uint(bitsinvert(bits0)) + 1 = bits2uint(false ' + bitsinvert(bits0) +1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
true ∈ bits0, false ∈ bits0 ⊦ bits2uint(bitsinvert(bits0)) + 1 = bits2uint(bitsinvert(bits0) +1)

Rule argument

Additional information

Used simplifier rules: bits2uint-zeros-03: ⊦ bits2uint(false ' + bits) = bits2uint(bits);% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;