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Proof step 4 from proof bits2int-rec-03 (previous step)

false ∈ bits0 ⊦ bits2uint(bitsinvert(bits0)) + 1 = bits2uint((false ' + bitsinvert(bits0))+1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ true ∈ bits0 → (bits + bitsinvert(bits0))+1 = bits + bitsinvert(bits0) +1
Proof step 6:
¬ true ∈ bits0, false ∈ bits0 ⊦ bits2uint(bitsinvert(bits0)) + 1 = bits2uint((false ' + bitsinvert(bits0))+1)
Proof step 9:
true ∈ bits0, false ∈ bits0 ⊦ bits2uint(bitsinvert(bits0)) + 1 = bits2uint(false ' + bitsinvert(bits0) +1)

Rule argument

seq: ⊦ true ∈ bits0 → (bits + bitsinvert(bits0))+1 = bits + bitsinvert(bits0) +1 subst: [bits0, bits] → [bits0, false '] rotate: F spec: bitopsaux inst: name: succ-zero-02

Additional information

Used terms: bits0, false '